Required knowledge
Basic C programming, Singly Linked List, Dynamic memory allocationAlgorithm to reverse a Singly Linked List
Algorithm to reverse a Singly Linked List %%Input : head node of the linked list Begin: If (head != NULL) then prevNode ← head head ← head.next curNode ← head prevNode.next ← NULL While (head != NULL) do head ← head.next curNode.next ← prevNode prevNode ← curNode curNode ← head End while head ← prevNode End if End
Steps to reverse a Singly Linked List
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Create two more pointers other than head namely prevNode and curNode that will hold the reference of previous node and current node respectively.
Make sure that prevNode points to first node i.e. prevNode = head.
head should now point to its next node i.e. the second node head = head->next.
curNode should also points to the second node i.e. curNode = head. -
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Now, disconnect the previous node i.e. the first node from others. We will make sure that it points to none. As this node is going to be our last node. Perform operation prevNode->next = NULL.
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Move the head node to its next node i.e. head = head->next.
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Now, re-connect the current node to its previous node i.e. curNode->next = prevNode;.
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Point the previous node to current node and current node to head node. Means they should now point to prevNode = curNode; and curNode = head.
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Repeat steps 3-5 till head pointer becomes NULL.
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Now, after all nodes has been re-connected in the reverse order. Make the last node as the first node. Means the head pointer should point to prevNode pointer. Perform head = prevNode;. And finally you end up with a reversed linked list of its original.
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Program to revere a Singly Linked List
/** * C program to reverse a Singly Linked List */ #include <stdio.h> #include <stdlib.h> /* Structure of a node */ struct node { int data; //Data part struct node *next; //Address part }*head; void createList(int n); void reverseList(); void displayList(); int main() { int n, choice; /* * Creates a singly linked list of n nodes */ printf("Enter the total number of nodes: "); scanf("%d", &n); createList(n); printf("\nData in the list \n"); displayList(); /* * Reverses the list */ printf("\nPress 1 to reverse the order of singly linked list\n"); scanf("%d", &choice); if(choice == 1) { reverseList(); } printf("\nData in the list\n"); displayList(); return 0; } /* * Create a list of n nodes */ void createList(int n) { struct node *newNode, *temp; int data, i; head = (struct node *)malloc(sizeof(struct node)); /* * If unable to allocate memory for head node */ if(head == NULL) { printf("Unable to allocate memory."); } else { /* * Reads data of node from the user */ printf("Enter the data of node 1: "); scanf("%d", &data); head->data = data; //Links the data field with data head->next = NULL; //Links the address field to NULL temp = head; /* * Creates n nodes and adds to linked list */ for(i=2; i<=n; i++) { newNode = (struct node *)malloc(sizeof(struct node)); /* If memory is not allocated for newNode */ if(newNode == NULL) { printf("Unable to allocate memory."); break; } else { printf("Enter the data of node %d: ", i); scanf("%d", &data); newNode->data = data; //Links the data field of newNode with data newNode->next = NULL; //Links the address field of newNode with NULL temp->next = newNode; //Links previous node i.e. temp to the newNode temp = temp->next; } } printf("SINGLY LINKED LIST CREATED SUCCESSFULLY\n"); } } /* * Reverse the order of nodes of a singly linked list */ void reverseList() { struct node *prevNode, *curNode; if(head != NULL) { prevNode = head; curNode = head->next; head = head->next; prevNode->next = NULL; //Makes the first node as last node while(head != NULL) { head = head->next; curNode->next = prevNode; prevNode = curNode; curNode = head; } head = prevNode; //Makes the last node as head printf("SUCCESSFULLY REVERSED LIST\n"); } } /* * Displays the entire list */ void displayList() { struct node *temp; /* * If the list is empty i.e. head = NULL */ if(head == NULL) { printf("List is empty."); } else { temp = head; while(temp != NULL) { printf("Data = %d\n", temp->data); //Prints the data of current node temp = temp->next; //Advances the position of current node } } }
Output
Enter the total number of nodes: 5
Enter the data of node 1: 10
Enter the data of node 2: 20
Enter the data of node 3: 30
Enter the data of node 4: 40
Enter the data of node 5: 50
SINGLY LINKED LIST CREATED SUCCESSFULLY
Data in the list
Data = 10
Data = 20
Data = 30
Data = 40
Data = 50
Press 1 to reverse the order of singly linked list
1
SUCCESSFULLY REVERSED LIST
Data in the list
Data = 50
Data = 40
Data = 30
Data = 20
Data = 10
Enter the data of node 1: 10
Enter the data of node 2: 20
Enter the data of node 3: 30
Enter the data of node 4: 40
Enter the data of node 5: 50
SINGLY LINKED LIST CREATED SUCCESSFULLY
Data in the list
Data = 10
Data = 20
Data = 30
Data = 40
Data = 50
Press 1 to reverse the order of singly linked list
1
SUCCESSFULLY REVERSED LIST
Data in the list
Data = 50
Data = 40
Data = 30
Data = 20
Data = 10
Happy coding ;)
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