Number pattern 36 in C

1
2 3
4 5 6 7
8 9 1 2 3 4 5 6
7 8 9 1 2 3 4 5 6 7 8 9 1 2 3 4

Required knowledge

Logic to print given pattern

1
2 3
4 5 6 7
8 9 1 2 3 4 5 6
7 8 9 1 2 3 4 5 6 7 8 9 1 2 3 4

1. It contains of N rows (where N is the total rows to be printed).
2. Each row contains exactly double column as in previous row. And the first row contains 1 column.
3. As per each column contains an integer from 1 to 9 in increasing order. When the number count reaches 10 it restarts to 1.

Program to print the given pattern

/**
 * C program to print the given number pattern
 */

#include <stdio.h>

int main()
{
    int i, j, N, colCount, value;

    colCount = 1;
    value = 1;

    printf("Enter rows: ");
    scanf("%d", &N);

    for(i=1; i<=N; i++)
    {
        for(j=1; j<=colCount; j++)
        {
            if(value == 10)
                value = 1; //Restart at 10

            printf("%d ", value);

            value++;
        }

        printf("\n");

        //Increases the total number of columns by 2
        colCount *= 2;
    }

    return 0;
}

Screenshot